help for Dungeons and Dragons Dice
Back to General discussions forum
the solution to
9 17 17 20 23 19 18 19 21 11 24 18 16 9 10 21 16 14 21 23 19 13 16 20 17 17 13 22 14 18 13 15 16 16 22 23 22 18 27 12 17 22 17 10 12 21 17 18 15 21 20 19 18 24 12 21 17 17 28 15 17 22 14 19 19 15 23 15 26 17 17 14 18 19 17 18 16 23 21 18 18 20 23 18 22 15 18 24 24 24 19 20 18 16 22 24 13 9 10 16 0 33 31 23 23 21 35 28 25 37 24 17 23 30 29 33 27 23 31 36 30 17 29 30 28 24 30 16 34 40 29 21 37 29 22 20 16 27 20 31 20 27 16 31 15 26 19 31 16 34 37 31 15 22 33 35 22 31 27 40 35 15 26 20 27 18 33 27 23 34 16 24 27 18 35 32 22 26 23 9 32 20 31 27 23 24 9 26 28 23 21 23 22 24 19 29 34 29 25 30 21 0 6 10 7 8 9 5 7 11 11 8 7 7 7 7 6 7 8 8 6 4 7 9 7 8 9 7 7 7 5 8 9 8 11 7 11 8 7 6 8 10 9 8 8 7 7 6 10 9 3 10 7 7 9 8 4 7 12 10 8 6 10 5 9 5 8 9 6 3 12 9 10 9 9 6 7 9 10 9 9 8 6 8 8 7 9 7 6 5 5 11 9 8 10 7 7 6 9 3 3 9 0
is 4d8 4d12 3d4
but isn't my solution 3d10 4d10 1d12 valid?
why the checker doesnt accept it???
Hi there!
but isn't my solution 3d10 4d10 1d12 valid?
well, you see, this problem is about statistics. Though some answers are technically possible they are not probable. And the goal is to guess the most fitting answer in the sense of probability.
You seem to choose answer according to lower and upper bound of the values, but that is not enough.
Let's see an example with the last line. You suppose it is result of casting 1d12. However, if such a die is cast
all values from 1 to 12 have equal probability. Meanwhile we don't see any 1, 2 here (though of 100 attempts
here should be about eight times for each number, right?)
Let's check the histogram of the results of this last case:
1 0
2 0
3 4
4 2
5 6
6 11
7 24
8 18
9 19
10 9
11 5
12 2
13 0
You see it really don't look like all numbers from 1 to 12 have equal probabilities, so it's something other.
Also keep in mind that sometimes answers are close, like 4d10 and 4d12 to be distinguished by just 100 casts,
so you may need to attempt submission several times to pass (as it is said in problem statement)...
Hope this helps :)
thanks I will reconsider my approach